Physics and Maths Tutoring from Michael A Smith.

Warm-up:

The Problem:

Find $x$ .

{(2021)}^{0} + {(2022)}^{1} - {(2023)}^{x} = 0

-/|\-

Solution:

An easy one to see the new year in with.
The first term, ${(2021)}^{0} = 1$ as any number raised to the zeroth power is one (if it's not zero), and
the second term, ${(2022)}^{1} = 2022$ as any number raised to the power of one is that number.
So, the first two terms sum to

{(2021)}^{0} + {(2022)}^{1} = 1 + 2022 = 2023

Now our equation simplifies to $2023 - {(2023)}^{x} = 0$ ,
and further to ${(2023)}^{x} = 2023$

Hence, $x = 1$ .

-oOo-

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